I need to short 2 pins on an camera to trigger it. Is there a way to do this directly from a pixhawk? Or perhaps I have to make an external relay circuit driven by the pixhawk? I have tried several RC switches with no luck.

http://www.hobbyking.com/hobbyking/store/__46040__Turnigy_Receiver_...

http://www.hobbyking.com/hobbyking/store/__43894__Dr_Mad_Thrust_Ele...

Both of these seem more like they are intended as power supplies and not as actual "switches" or "relays".

The Pixhawk has a "relay" setting, but I guess that is intended to drive a relay, not actually "be" a relay?

I have ordered a picoswitch and I think that will work. But I'm just curious what other solutions may exist...

Thanks!

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I have the cam trigger you need if you can't get it elsewhere.

Connect to Aux 6 on Pixhawk.

Do you sell the trigger cable? 

 Here is a relay that is designed for use in RC systems. https://www.pololu.com/product/2804

Yes I can make one up for you. It does however needed to be connected (soldered) to the camera shutter button. 

Or I can hard wire it for you.

What exactly are you hoping to achieve with it? 

We made it to give the most rapid possible capture rate - gives good overlap in windy conditions for one thing.

I'm looking for a cable to connect a Canon camera to the Pixhawk for auto missions and triggering. Thanks for replying.

The older px4fmu/px4io combo had relay switches built-in you could use exactly the way you want. Unfortunately this useful feature was dropped from the Pixhawk integrated design.

This is the schematic that works (I'm told)

Hi guyes,

I'm trying to short 2 pins inside a GoPro remote to trigger the camera shutter and have tried a circuit I found in another, older thread. Unfortunately it provides power to the reed relay when the relay is off (0v on the Pixhawk pin) and opens the relay once the relay should be on (3.3v on the Pixhawk pin).

Does anyone know if I can drop 2nd 2N7000 and connect the relay to the first one instead like in the 2nd Diagram below? Or are there issues with that design?

Thanks a lot,

Eric

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