There has been some question on the strength of a 3d printed quadcopter I had some wonders myself as to just how strong it was so I put this little test together not bad for a frame that weighs 636 grams

• Abs is lighter and stronger for the modifications,there was a post here where an air frame was printed with a nylon type filament.

diydrones.com/profiles/blogs/uav-fuselage-3d-printed-in-nylon-for-l...

Might even shave some more grams and allow for thinner walls.

• Yes I agree it is at around 16% infill at the moment and the skin thickness is thicker than it needs to be we can definitely shave quite a few grams off that with some fine tuneing might be able to squeeze a few more min out of the flight time but with 46 min of flight time already not sure the extra strength isn't a bonus
• MR60

Impressive resistance for PLA. Now it would be nice to make the following experiments:

-reduce the infill parameters by 10% in your printer

-measure the resistance

-repeat until you get the lightest frame as possible that can still sustain a reasonable weight (it is useless to support 27Kg and it adds unecessary weight. 600+ grams is relatively heavy for a quad frame)

• Nope but my  Airframe can do this

PX32 flying wing got Folded and Parked on. not sure if it would surbive a dynamic load on a collision with a light aircraft. given it doesn't enter the Prop.

• Weight the 6 cell weighs 1 pound more and these motors run great on 4s
• Why did you choose 4s over 6s?

• wow! 27 kg is 270 newtons. Then it's really good strength

• Ok, while the bricks are on the copter him a force F = mg. Suppose bricks weigh 10kg. Take the acceleration of free fall for the convenience of g = 10 m / s ^ 2. Получим F=10*10=100 newtons.

Now suppose copter falls. For example with a height of 2 meters. Speed in the moment of impact on the ground will be calculated by the formula V= sqrt(2*H*g) =sqrt(2*2*10)=sqrt(40)=6.3 m/s. It is known that the attack does not happen instantaneously. Always have some flexibility and plasticity of the material. Suppose impact copter caved 2 cm (0.01 m). Shot at the same time is computed as t=2*S/V=2*0.01/6.3=0.006 s (6ms). It is not difficult to calculate the acceleration of the copter on impact. Calculated by the formula a=V/t=6.3/0.006=1050m/s^2. Calculate the force by the formula F=m*a=2.5*1050=2625 newtons (260 kg in static load). Of course it's rough calculations and practice fall will be softer and the load will be several times smaller. Although if you are not going to drop your copter then everything will be fine :)

• Now that's funny
• Moderator

Now that's what I call mass-balancing!